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316

0

f

f

S

K K

σ

− =

(22)

One needs to evaluate both terms in Eq. (22), using a procedure similar to the one used

in previous section for the averages. Now the following scheme is applied

i

i

0

0

0

0

1/2

2

,

0

1/2

2

,

0

1

( , , )

1

( , , )

c a

f

f

c c a

c

c a

f

f

S

S

S

c c a

c

K K

K c R dc

a

K K

K c R dc

a

σ

σ

σ

α

α

+

+

+

+

= ⎨

= ⎨

(23)

The resulting functions depend on the fractal exponent

α

and two length-like variables

X

and

R

. To calculate the

K

-factors for a fractal crack the expression given by Wnuk and

Yavari /27 allows to obtain

1

2

2

2 1/2

2 2

0

(

)

(

)

( )

a

f

a

a x

a x

K

p x dx

a x

α

α

α

σ

α

π

+ + −

=

(24)

In the first equation in (23) the substituting

σ

for

p

(

x

) and

c

+

R

for

a

leads to

( , , )

( )

(

)

f

K c R

c R

α

σ

α

χ α σ π

=

+

(25)

The scalar function appearing in this equation reads

2

2

1

2

2

0

1 (1 ) (1 )

( )

(1 )

s

s ds

s

α

α

α

α

χ α

π

+

=

(26)

Next evaluation of the average produces

0

1/2

1/2

1

2

2

2

2

0

0

0

1

( )

(

)

( )

( '

)

'

c a

X

f

c

X

K

a

c R dc

a

X R dX

a

α

α

α

α

σ

χ α σ π

χ α σ π

+

+

=

+

=

+

(27)

The integral is elementary and one can obtain

1/2

2 1

2 1

2

0

(

1)

(

)

( )

2 1

f

X R

X R

K

a

α

α

α

σ

χ α σ π

α

+

+

+ +

− +

=

+

(28)

It is readily observed that for the fractal dimension

1

D

(or

1/ 2

α

) expression

(28) reduces to the equation valid for non-fractal discretized cohesive model

1/2

0

1

2

K

a X R

σ

σ π

=

+ +

(29)

Let us define the ratio of the last two

K

-factors

1/2

0

( , , )

f

f

K

k

a

X R

K

σ

α

σ

σ

σ

χ

α

=

=

(30)

where the new scalar function is defined as follows

1/2

2 1

2 1

(

1)

(

)

( , , )

( )

1

(2 1)(

)

2

X R

X R

X R

X R

α

α

σ

χ

α

χ α

α

+

+

+ +

− +

=

+ + +

(31)